x^2(x-4)+15(x-4)=0

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Solution for x^2(x-4)+15(x-4)=0 equation: 


Simplifying
x2(x + -4) + 15(x + -4) = 0

Reorder the terms:
x2(-4 + x) + 15(x + -4) = 0
(-4 * x2 + x * x2) + 15(x + -4) = 0
(-4x2 + x3) + 15(x + -4) = 0

Reorder the terms:
-4x2 + x3 + 15(-4 + x) = 0
-4x2 + x3 + (-4 * 15 + x * 15) = 0
-4x2 + x3 + (-60 + 15x) = 0

Reorder the terms:
-60 + 15x + -4x2 + x3 = 0

Solving
-60 + 15x + -4x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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